[HBase programming, IR, Java]檢索條件值的關係為AND 或者是OR (Boolean retrieval)

假設每個值之間以空白間隔

String qryKeywords = "竹筍 豆皮 好吃 開心";



Condition 1:
查詢條件之間以"和"關係存在( The terms in a query are linked together with AND)

ArrayList<Filter> filtersArrayList = new ArrayList<Filter>(); 
Filter filter = null;
String [] qryKeywordsList =qryKeywords.split("\\s+");


for (int i=0; i< qryKeywordsList.length; i++){

if (!qryKeywordsList[i].equals("")){
filter= new ValueFilter(CompareFilter.CompareOp.EQUAL,new SubstringComparator(qryKeywordsList[i]));    
filtersArrayList.add(filter);
}
}


Scan s =  new  Scan(); 
s.setFilter(filtersArrayList);  
ResultScanner rs = table.getScanner(s);  
while ((r = rs.next()) != null) {
for (KeyValue kv : r.list())  
                System.out.println( "row : " + new  String(kv.getRow()));  
                System.out.println( "column : " + new  String(kv.getColumn()));  
                System.out.println( "value : " + new  String(kv.getValue()));  
        }  
}  



Condition 2:
查詢條件之間以"或"關係存在(The terms in a query are linked together with OR)
==>利用RegexStringComparator


ArrayList<Filter> filtersArrayList = new ArrayList<Filter>(); 
Filter filter = null;
String qryKeywordsReg =qryKeywords.replaceAll("\\s+", "|");
filter= new ValueFilter(CompareFilter.CompareOp.EQUAL,new RegexStringComparator(qryKeywordsReg));    
filtersArrayList.add(filter);


Scan s =  new  Scan(); 
s.setFilter(filtersArrayList);  
ResultScanner rs = table.getScanner(s);  
while ((r = rs.next()) != null) {
for (KeyValue kv : r.list())  
                System.out.println( "row key : " + new  String(kv.getRow()));  
                System.out.println( "column : " + new  String(kv.getColumn()));  
                System.out.println( "value : " + new  String(kv.getValue()));  
        }  
}